Parameters
- stream
- Stream from which to load
Return Value
true if successful; false otherwise
string fileName; fileName = "D:\\mine.xml"; System.IO.Stream stream; stream = System.IO.File.Open(fileName, System.IO.FileMode.Open); FpSpread1.Open(stream);
Dim fileName As String fileName = "D:\mine.xml" Dim stream As System.IO.Stream stream = System.IO.File.Open(fileName, System.IO.FileMode.Open) FpSpread1.Open(stream)