Deserialize Method (ListBoxCellType)

Visual Basic
C#

'Declaration
 
Public Overridable Function Deserialize( _
   ByVal r As XmlNodeReader _
) As Boolean

'Usage
 
Dim instance As ListBoxCellType
Dim r As XmlNodeReader
Dim value As Boolean
 
value = instance.Deserialize(r)

public virtual bool Deserialize( 
   XmlNodeReader r
)

Parameters

r: XmlNodeReader from which to read (load) the object

Return Value

Boolean: true if successful; false otherwise

This example shows the use of this method for a currency cell but the use is similar for any cell type.

C#

FarPoint.Win.Spread.CellType.CurrencyCellType curr = new FarPoint.Win.Spread.CellType.CurrencyCellType();
curr.DecimalSeparator = ",";
curr.DecimalPlaces = 3;
fpSpread1.ActiveSheet.Cells[0, 0].CellType = curr;
fpSpread1.ActiveSheet.Cells[0, 0].Value = 443.0908;
bool b; 
System.Xml.XmlDocument doc = new System.Xml.XmlDocument(); 
doc.Load("..\\files\\mycurr.xml"); 
System.Xml.XmlNode node;  
node = doc.FirstChild; 
while (!node.Name.Equals("Currency")) 
    node = node.NextSibling; 
System.Xml.XmlNodeReader r = new System.Xml.XmlNodeReader(node); 
r.Read(); 
b = curr.Deserialize(r); 
listBox1.Items.Add(b.ToString());

Visual Basic

Dim curr As New FarPoint.Win.Spread.CellType.CurrencyCellType()
curr.DecimalSeparator = ","
curr.DecimalPlaces = 3
FpSpread1.ActiveSheet.Cells(0, 0).CellType = curr
FpSpread1.ActiveSheet.Cells(0, 0).Value = 443.9098
Dim b As Boolean
Dim doc As New System.Xml.XmlDocument()
doc.Load("..\files\mycurr.xml")
Dim node As System.Xml.XmlNode
node = doc.FirstChild
While Not (node.Name.Equals("Currency"))
node = node.NextSibling
End While
Dim r As New System.Xml.XmlNodeReader(node)
r.Read()
b = curr.Deserialize(r)
ListBox1.Items.Add(b)

Target Platforms: Windows 2000 Professional (SP4), Windows 2000 Server, Windows 2003 Server (SP1), Windows Server 2012 R2, Windows 2008, Windows XP (SP2), Windows Vista, Windows 7, Windows 8, Windows 8.1, Windows 10

Reference

ListBoxCellType Class
ListBoxCellType Members