OpenExcel(String,Int32) Method

Opens an Excel file and loads the specified sheet (by number) from that file into this sheet.

Syntax

Visual Basic
C#

'Declaration
 
Public Overloads Function OpenExcel( _
   ByVal fileName As String, _
   ByVal excelSheetIndex As Integer _
) As Boolean

'Usage
 
Dim instance As SheetView
Dim fileName As String
Dim excelSheetIndex As Integer
Dim value As Boolean
 
value = instance.OpenExcel(fileName, excelSheetIndex)

public bool OpenExcel( 
   string fileName,
   int excelSheetIndex
)

Parameters

fileName: Path and name of the file to open
excelSheetIndex: Index of the sheet to load from the file

Return Value

Boolean: true if successful; false otherwise

Example

This example open an Excel file and loads it in the active sheet.

OpenFileDialog ofd = new OpenFileDialog();
string s;
ofd.Filter = "Excel files (*.xls)|*.xls";
ofd.FilterIndex = 2;
ofd.InitialDirectory = Application.StartupPath;
ofd.RestoreDirectory = true;
if (ofd.ShowDialog() == DialogResult.OK) 
{
    s = ofd.FileName;
    fpSpread1.ActiveSheet.OpenExcel(s, 0);
}

Visual Basic

Dim s As String
Dim ofd As New OpenFileDialog()
ofd.Filter = "Excel files (*.xls)|*.xls"
ofd.FilterIndex = 2
ofd.InitialDirectory = Application.StartupPath
ofd.RestoreDirectory = True
If ofd.ShowDialog() = DialogResult.OK Then
    s = ofd.FileName
    FpSpread1.ActiveSheet.OpenExcel(s, 0)
End If

Reference

SheetView Class
SheetView Members
Overload List