Deserialize Method (RichTextCellType)

Visual Basic
C#

'Declaration
 
Public Overridable Function Deserialize( _
   ByVal r As XmlNodeReader _
) As Boolean

'Usage
 
Dim instance As RichTextCellType
Dim r As XmlNodeReader
Dim value As Boolean
 
value = instance.Deserialize(r)

public virtual bool Deserialize( 
   XmlNodeReader r
)

Parameters

r: XmlNodeReader from which to read (load) the object

Return Value

Boolean: true if successful; false otherwise

This example shows the use of this method for a currency cell but the use is similar for any cell type.

C#

FarPoint.Win.Spread.CellType.CurrencyCellType curr = new FarPoint.Win.Spread.CellType.CurrencyCellType();
curr.DecimalSeparator = ",";
curr.DecimalPlaces = 3;
fpSpread1.ActiveSheet.Cells[0, 0].CellType = curr;
fpSpread1.ActiveSheet.Cells[0, 0].Value = 443.0908;
bool b; 
System.Xml.XmlDocument doc = new System.Xml.XmlDocument(); 
doc.Load("..\\files\\mycurr.xml"); 
System.Xml.XmlNode node;  
node = doc.FirstChild; 
while (!node.Name.Equals("Currency")) 
    node = node.NextSibling; 
System.Xml.XmlNodeReader r = new System.Xml.XmlNodeReader(node); 
r.Read(); 
b = curr.Deserialize(r); 
listBox1.Items.Add(b.ToString());

Visual Basic

Dim curr As New FarPoint.Win.Spread.CellType.CurrencyCellType()
curr.DecimalSeparator = ","
curr.DecimalPlaces = 3
fpSpread1.ActiveSheet.Cells(0, 0).CellType = curr
fpSpread1.ActiveSheet.Cells(0, 0).Value = 443.9098
Dim b As Boolean
Dim doc As New System.Xml.XmlDocument()
doc.Load("..\files\mycurr.xml")
Dim node As System.Xml.XmlNode
node = doc.FirstChild
While Not (node.Name.Equals("Currency"))
node = node.NextSibling
End While
Dim r As New System.Xml.XmlNodeReader(node)
r.Read()
b = curr.Deserialize(r)
ListBox1.Items.Add(b)

Reference

RichTextCellType Class
RichTextCellType Members