ImageCellType Constructor()

Visual Basic
C#

'Declaration
 
Public Function New()

'Usage
 
Dim instance As New ImageCellType()

public ImageCellType()

This example creates a cell of this type, sets properties of this cell type, and assigns this cell type to a row of cells.

C#

FarPoint.Win.Spread.CellType.ImageCellType icelltype =new FarPoint.Win.Spread.CellType.ImageCellType();
icelltype.Style = FarPoint.Win.RenderStyle.Stretch;
icelltype.TransparencyColor = Color.Black;
icelltype.TransparencyTolerance = 100;
fpSpread1.Sheets[0].Rows[0].CellType =icelltype;
System.Drawing.Image image = System.Drawing.Image.FromFile("D:\\alphaomega3.jpg"); 
System.IO.MemoryStream stream = new System.IO.MemoryStream();
byte[] bytes;
string str;
image.Save(stream,System.Drawing.Imaging.ImageFormat.Jpeg);
stream.Seek(0, System.IO.SeekOrigin.Begin); 
bytes = stream.GetBuffer();
str = System.Convert.ToBase64String(bytes);
fpSpread1.Sheets[0].Cells[0,0].Value = image;
fpSpread1.Sheets[0].Cells[0,1].Value = bytes;
fpSpread1.Sheets[0].Cells[0,2].Value = str;

Visual Basic

Dim icelltype As New FarPoint.Win.Spread.CellType.ImageCellType
icelltype.Style = FarPoint.Win.RenderStyle.Stretch
icelltype.TransparencyColor = Color.Black
icelltype.TransparencyTolerance = 100
FpSpread1.Sheets(0).Rows(0).CellType = icelltype
Dim image As System.Drawing.Image = System.Drawing.Image.FromFile("D:\alphaomega3.jpg")
Dim stream As New System.IO.MemoryStream
Dim bytes As Byte()
Dim str As String
image.Save(stream, System.Drawing.Imaging.ImageFormat.Jpeg)
stream.Seek(0, System.IO.SeekOrigin.Begin)
bytes = stream.GetBuffer()
str = System.Convert.ToBase64String(bytes)
FpSpread1.Sheets(0).Cells(0, 0).Value = image
FpSpread1.Sheets(0).Cells(0, 1).Value = bytes
FpSpread1.Sheets(0).Cells(0, 2).Value = str

Reference

ImageCellType Class
ImageCellType Members
Overload List